請問 (1+r)7次方=3.6983 點計呢?

(1+r)^7=3.6983
7log(1+r)=log3.6983=0.56800
log(1+r)=0.56800/7=0.08114
1+r=10^0.08114=1.2054
r=0.2054

逆向番佢-.-

1+r=7√3.6983
=1.205433239

再減1
=0.25433239