請問 (1+r)7次方=3.6983 點計呢?
謝謝~
請問 (1+r)7次方=3.6983 點計呢?
2008-08-18 10:06 pm
回答 (2)
2008-08-18 10:16 pm
✔ 最佳答案
(1+r)^7=3.69837log(1+r)=log3.6983=0.56800
log(1+r)=0.56800/7=0.08114
1+r=10^0.08114=1.2054
r=0.2054
參考: me
2008-08-18 10:09 pm
逆向番佢-.-
1+r=7√3.6983
=1.205433239
再減1
=0.25433239
1+r=7√3.6983
=1.205433239
再減1
=0.25433239
收錄日期: 2021-05-03 06:57:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080818000051KK01543