fast!!!
1. a^5+b^5-(ab)^2(a+b)
等於??
多次元公式
2008-08-16 8:49 pm
回答 (2)
2008-08-16 9:11 pm
✔ 最佳答案
a^5 + b^5 - (ab)^2(a+b) = a^5 + b^5 - a^3b^2 - a^2b^3= a^3(a^2 - b^2) - b^3(-b^2 + a^2)
= (a^3 - b^3)(a^2 - b^2) = (a-b)(a^2 + ab + b^2)(a +b)(a-b)
= (a +b)(a-b)^2(a^2 + ab + b^2).
2008-08-16 8:58 pm
a5+b5-(ab)2(a+b)
=a5+b5-a3b2-a2b3
2008-08-17 23:26:38 補充：
其實我唔太明白你的問題,你給下面最佳~
=a5+b5-a3b2-a2b3
2008-08-17 23:26:38 補充：
其實我唔太明白你的問題,你給下面最佳~
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080816000051KK01018