數學數學數學``{急}

2008-08-16 3:09 am
下列計算中的括住{}的部分出了錯,嘗試把錯處改正。

1. 2^3x3^2{=(2x3)^3+2=6^5}

2. (-a^2)^3{=a^2x3=a^6}

3. (a^2)^3{=a^5)

4. a^10‧a^2/a^5‧a^6{=a^10+2-5+6}=a^13

化簡下列各數式。

(a)﹝x^3/y^2﹞^4‧(x^2y)^3

(b)a^2xa^3xb^4/(a^2b)^3

(c) (-4a)^3/(-2ab)^2

回答 (1)

2008-08-16 7:09 pm
✔ 最佳答案
1. 2^3x3^2 = 2x(2^2)x(3^2) = 2x(3x2)^2 = 2 x 6^2 = 2 x 36 = 72

2. (-a^2)^3 = (-1)^3 x (a^2)^3 = - a^(2x3) = -a^6

3. (a^2)^3 = a^(2x3) = a^6

4. a^10‧a^2/a^5‧a^6 = a^[(10+2)-(5+6)] = a^1 = a

化簡下列各數式。

(a)﹝x^3/y^2﹞^4‧(x^2y)^3
= x^[(3)(4)+(2)(3)] y^[(-2)(4)+3] = x^18/ y^5
(b)a^2xa^3xb^4/(a^2b)^3
= a^[2+3-(2x3)] b^(4-3) = a^(-1) b^1 = b/a
(c) (-4a)^3/(-2ab)^2
= (-4)^3 a^(3-2)/[(-2)^2 b^2]
= -64a / (4b^2)
= -16a / b^2


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