A bag contains some $5 and $10 coins. There are althgether 120 coins in the bag and the total amount is $810. Find the number of $5 coins and that of $10 coins in the bag.
[要列式同答案]
THX=)
我想問一條MATHS題(ENG)
2008-08-15 11:09 pm
回答 (2)
2008-08-15 11:36 pm
✔ 最佳答案
Let x be the number of $5 coins.5x+(120-x)10=810
5x+1200-10x=810
5x-10x=810-1200
-5x=-390
-5x/-5=-390/-5
x=78
( )The number of $5 coins is 78.
The number of $10 coins,
120-x
=120-78
=42
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參考: 我的知識
2008-08-15 11:17 pm
二元一次方程
Let x be the amount of $5 coins
Let y be the amount of $10 coins
x + y =120
5x +10y = 810
Let x be the amount of $5 coins
Let y be the amount of $10 coins
x + y =120
5x +10y = 810
參考: Maths teacher
收錄日期: 2021-04-24 23:09:33
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