(x-6)(3x-5)=0? Help me out w/ this please!?

(x-6)(3x-5)=0
(x-6)= 0 / (3x-5) ( OR ) (3x-5) = 0 / (x-6)
x = 6 (OR) x = 5/3


Hope this helps............

(x - 6)(3x - 5) = 0

x - 6 = 0
x = 6

3x - 5 = 0
3x = 5
x = 5/3

∴ x = 5/3 , 6

Here L.H.S.=R.HS. only when either of (x-6) or (3x-5) = 0
or i mean either x = 6 or x = 5/3.
And yes, by solving this problem it actually means finding the values of x for which the equation stands correct. And you can easily verify your answers.
Hope I Helped............

it is only possible if either x=6 or x=5/3 .

Well without telling you the answer you would first multiply "x-6" by "3x-5" and then you would group like terms and then you can solve the quadratic by completing the square, the quadratic formula, and various other methods like graphs.

note
x - 6 = 0
x = 6
and
3x - 5 = 0
3x = 5
x = 5/3

x = 6 , x = 5/3