how to solve statement like these:x+y+z=10 , 2x+2y+2z=20 ,solve value of x,y,z?

There's nothing you can do. Those are just of the same plane (at least, I'm pretty sure its a plane). If you notice, the second equation is just 2 times the first one. So, there are an infinite number of solutions.

Hi this is Saranyan !

actually when there are 3 variables in a equation
3 equations should be given to find a common point

but here in this situation

x+y+z=10

and

2x+2y+2z=20
=>
taking 2 as common
2(x+y+z)=20
x+y+z=20/2
x+y+z=10

therefore both of your given equations are same

they have infinitely common points in a graph as they are same equation


some solutions are

(6,2,2)
(2,6,2
(2,2,6)
(3,3,4)

like dat many !

The answer is not unique.
Any answer where x+y+z=10 is an answer.
For example, x=1 y=2 z=7
or x=2 y=3 z=5
or x=3 y=6 z=1 etc etc etc, an infinite number of possibilities
ANSWER

x, y, and z can be any numbers.. from the second equation,
2x+2y+2z=20, 2(x+y+z) = 20, (x+y+z) = 10.. this is the same as the first equation.. that means both equations are always real..x can be 4, y be 4 and z be 2, x can be -1 y be 11 and z be 0.. there are infinite possibilities

2x + 2y + 2z = 20
=> x + y + z = 10.

Thus, both given equations are the same and all values of x, y, z such that x + y + z = 10 satisfy both the equations simultaneously. There are infinite solutions one of which, for example is x=1, y=2, z =7.

i dont think you can because u dont have sufficient info/ equation to solve it.. with 3 unknowns, x , y, and z u have to have at least 3 equation and 2x+2y+2z=20 is also x+y+z=10 because if u divide 2x+2y+2z=20 all by 2 u will have x+y+z=10
try to extract extra info from ur question
goodluck

x=3 y=3 z=4

a million) From the 1st equation, x = 6 - 2y. Substituting this in (2), 2(6-2y)² + y² = 57 increasing and simplifying, 3y² - 16y + 5 = 0 Factorizing, this is: (y - 5)(3y - a million) = 0 ==> the two y = 5 or a million/3 whilst y = 5, x = -4 whilst y = a million/3, x = sixteen/3 as a result (x,y) = {(-4, 5), (sixteen/3, a million/3)}

X , y , z cannot be solved because you need to have 3 equations when you need to solve 3 variables.

Equations are one and the same.

If you have 3 unknowns , you require 3 equations.