Mulitply (3x+9)(2x^2+7x+9)?

(3x + 9)(2x² + 7x + 9)

1. Multiply 3x by each term in (2x² + 7x + 9) then multiply 9 by each term in (2x² + 7x + 9)

6x^3 + 21x² + 27x + 18x² + 63x + 81

2. Add the like terms together

6x^3 + 39x² + 90x + 81

(3x + 9)(2x^2 + 7x + 9)
= 3x*2x^2 + 9*2x^2 + 3x*7x + 9*7x + 3x*9 + 9*9
= 6x^3 + 18x^2 + 21x^2 + 63x + 27x + 81
= 6x^3 + 39x^2 + 90x + 81

6x³ + 21x² + 27x
____ 18x² + 63x + 81

6x³ + 39x² + 90x + 81

(3x + 9) (2x^2+7x+9)
First we multiply the 3x by all second section
6x^3+21x^2+18x
Then multiply 9 by the second section as we did in first
18x^2+63x+81
So it’s become
6x^3+21x^2+18x 18x^2+63x+81
Then we add the same
6x^3+39x^2+81x+81

I hope I did well

6x^3 + 21x^2 + 27x + 18x^2 + 63x + 81

6x^3 + 39x^2 + 90x + 81

just multiply everything in the first one by everything in the second and add them up

6x^3+21x^2+27x+18x^2+63x+81
6x^3+39x^2+90x+81

make it a good day