點樣可以平方差恆等式驗算

朋友, 我唔係幾明你想問d mud

不過根據你比個一條式, 可作以下運算:

a^2 - b^2 = (a-b)×11
(a - b) (a + b) = (a - b) x 11
(a - b) (a + b - 11) = 0

FROM THE ABOVE
(a - b) = 0 -------(1)
and (a + b - 11) = 0 -------(2)

From (1) , (a - b) = 0
a = b
From (2), (a + b - 11) = 0
2a = 11 (From (1))
a = 5.5
Then b = a = 5.5

2008-08-13 15:04:39 補充：
如果你條 a^2 - b^2 = (a-b)

咁 a 同 b 就係 任何數 都可成立