C an you Help me factor this completely

2008-08-11 3:56 pm
. Factor completely:
7x^2 58x 16

I got (x 8 ) (7x 2) but this equals out to

7x^2 56x 16
not the same as example above



更新1:

Thanks Guys, I see were i went wrong

回答 (8)

2008-08-11 4:07 pm
✔ 最佳答案
No. Your answer is right.
(x + 8) (7x + 2) = 7x² + 56x + 2x + 16 = 7x² + 58x + 16
2016-10-18 9:32 pm
ok so the variable is c u might desire to have (c+something)(c+something) and the numbers u use could upload as much as the b and multiply c of ur equation a = a million b= 4 c = 4 so what 2 numbers upload as much as 4 and multiply to 4...2 so while u element it ur solutions is (c+2)(c+2) desire i helped
2008-08-11 4:17 pm
7x^2 + 58x + 16
= 7x^2 + 56x + 2x + 16
= (7x^2 + 56x) + (2x + 16)
= 7x(x + 8) + 2(x + 8)
= (x + 8)(7x + 2)
2008-08-11 4:12 pm
7x^2+58x+16
7x^2+56x+2x+16
7x(x+8)+2(x+8)
(x+8)(7x+2)

Note:
16 x 7 = 112
56 x 2 = 112
split 58 as 56 & 2
2008-08-11 4:04 pm
(7x+2)(x+8) is correct

(7x)(x) + (7x)(8) + (2)(x) + (2)(8)

7x² + 56x + 2x + 16

7x²+58x+16
2008-08-11 4:03 pm
You got it right. Expanding it out: x^2 + 56x + 2x +16
2008-08-11 4:02 pm
7x^2 + 58x + 16
(7x + 2 ) (x + 8)

You have the correct factoring when you apply the FOIL method you see that the 7x * 8 is added to the additional 2 * x. Which gives you that additional 2x you were missing.

(7x + 2 ) (x + 8)
(7x * x) + ( 7x * 8) + (x * 2) + (2 * 8)
7x^2 + 56x + 2x + 16
7x^2 + 58x + 16
2008-08-11 4:02 pm
(x + 8)(7x + 2) = 7x^2 + 2x + 56x + 16, or

7x^2 + 58x + 16.

Looks like you just did your arithmetic wrong; the factoring was right.

Hope this helps.


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