Solving Equations in One Variable

bhE here it is

How do you SOLVE and CHECK this equations?
Substitute your answer to the give equation. If it equate then they are correct.

1. 3x = x 10
3x = x + 10
3x - x = 10
2x = 10
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Ans:::x=5
====================
here's how to check
3x = x + 10
3(5) = 5 + 10
15 = 15 ← check

2. 13 - c = 4 2c
13 - c = 4 + 2c
13 - 4 = 2c + c
9 = 3c
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Ans:::c= 3
========================

3. 3m - 8 m = 12 - 2m 10
3m - 8 + m = 12 - 2m + 10
4m - 8 = 22 - 2m
4m + 2m = 22 + 8
6m = 30
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Ans:::m = 5
=====================

4. 2(4x - 3) - (3x - 3) = 2
(8x - 6) - 3x + 3 = 2
5x = 2 + 6 - 3
5x = 5
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Ans:::x = 1
==================

5. x/3 x/2 = 5
x/3 + x/2 = 5 ← you can not add directly (do not have the same denominator.

LCD = 2 * 3 = 6

(2x + 3x)/6 = 5 ← simplified
5x = 30
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Ans ::: x = 6
=================
checking
[2(6) + 3(6)]/6 = 5
12 + 18 = 30
30 = 30 ← check

hope this helps

1st problem:
3x = x + 10
2x = 10
x = 5

2nd problem:
13 - c = 4 + 2c
3c = 9
c = 3

3rd problem:
3m - 8 + m = 12 - 2m + 10
6m = 30
m = 5

4th problem:
2(4x - 3) - (3x - 3) = 2
8x - 6 - 3x + 3 = 2
5x = 5
x = 1

5th problem:
x/3 + x/2 = 5
2x + 3x = 30
5x = 30
x = 6

ok, do it one step-at-time and you will locate that t = + a million: (a million) Algebraically upload "like" words: 9 - 6 = 3 and -t - t = -2t (2) So, on the left-ingredient, you have: 3 - 2t and on the the ultimate option you nevertheless have t (3) Now, upload 2t to the two factors and you at present have: 3 = 3t, in view that -2t + 2t = 0 (on the left ingredient) whilst t + 2t = 3t (on the the ultimate option ingredient) (4) ultimately, divide the two factors by utilising 3 and you at present have a million = t or (what's the comparable element) t = a million. notice: in case you are able to cope with uncomplicated arithmetic, you ought to no longer get right into a tangle. and don't be intimidated by utilising "variables"; in uncomplicated algebra, geometry, trig, and so on. they are in basic terms symbols that often designate numbers!!! additionally, you ought to get used to the "shorthand", which includes (in the above): 2t ability "2 greater desirable by utilising t", and -2t ability "minus a million greater desirable by utilising 2 greater desirable by utilising t", and the expression -2t + 2t = 0 ability that "that sum is often 0, no remember the fee of t", and so on. delight in!!!!

1.
3x = x + 10
x = 5

2.
13 - c = 4 - 2c
c = -9

3.
3m - 8 m = 12 - 2m - 10
3m = -2
m = -2/3

4.
2(4x - 3) - (3x - 3) = 2
5x = 5
x = 1

5.
x/3 + x/2 = 5
x = 6

Question 1
3x = x + 10
2x = 10
x = 5

Question 2
13 - c = 4 + 2c
9 = 3c
c = 3

Question 3 (poorly presented)
Can but guess at :-
3m - 8 + m = 12 - 2m + 10
4m - 8 = 22 - 2m
6m = 30
m = 5

Question 4
8x - 6 - 3x + 3 = 2
5x - 3 = 2
5x = 5
x = 1

Question 5
x/3 + x/2 = 5
2x + 3x = 30
5x = 30
x = 6

1)
3x = x + 10
3x - x = 10
2x = 10
x = 10/2
x = 5

2)
13 - c = 4 + 2c
-2c - c = 4 - 13
-3c = -9
c = -9/-3
c = 3

3)
3m - 8 + m = 12 - 2m + 10
3m + m + 2m = 12 + 8 + 10
6m = 30
m = 30/6
m = 5

4)
2(4x - 3) - (3x - 3) = 2
2*4x - 2*3 - 3x + 3 = 2
8x - 6 - 3x + 3 = 2
8x - 3x = 2 + 6 - 3
5x = 5
x = 5/5
x = 1

5)
x/3 + x/2 = 5
6(x/3 + x/2) = 6(5)
2(x) + 3(x) = 30
2x + 3x = 30
5x = 30
x = 30/5
x = 6

please complete your signs for each equation

1. is it 3X = X + 10 ?
2. is it 13 - C = 4 + 2C ?
etc ...

only then can we help you ...

1. x=0
2. 13 = 43 c
c = 13/43
3. -5m = 12 - 20m
15m = 12
m = 12/15 = 4/5 = .8
4. 8x - 6 - 3x + 3 = 2
5x -3 = 2
5x = 5
x = 1
5. doesn't make sense