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Simultaneous Equations Problem
2008-08-10 5:13 am
i saw some horses and noticed that there were 15 more legs than tails. Assuming each horse has 1 tail and 4 legs, how many horses did I see?
回答 (5)
2008-08-10 8:50 am
✔ 最佳答案
No. of tails (x):4x = x + 15
3x = 15
x = 5
No. of legs:
= 5 + 15
= 20
Answer: 5 horses based on their no. of tails is what you saw.
Checking (15 legs more than tails):
= 4 legs(5 horses) - 5 tails
= 20 legs - 5 tails
= 15
2008-08-11 10:31 am
T + 15 = L
4T = L
So sub in the 2nd to the 1st
t + 15 = 4t
15 = 4t - t
15 = 3t
t = 5
So there are 5 tails and therefore 5 horses.
4T = L
So sub in the 2nd to the 1st
t + 15 = 4t
15 = 4t - t
15 = 3t
t = 5
So there are 5 tails and therefore 5 horses.
2008-08-10 6:01 pm
x = legs
y = tails
x - 15 = y
4y = x (1 tail : 4 legs)
4y = x
4(x - 15) = x
4x - 60 = x
4x - x = 60
3x = 60
x = 60/3
x = 20
x - 15 = y
20 - 15 = y
y = 5
â´ x (legs) = 20 , y (tails) = 5
(You saw five horses.)
y = tails
x - 15 = y
4y = x (1 tail : 4 legs)
4y = x
4(x - 15) = x
4x - 60 = x
4x - x = 60
3x = 60
x = 60/3
x = 20
x - 15 = y
20 - 15 = y
y = 5
â´ x (legs) = 20 , y (tails) = 5
(You saw five horses.)
2008-08-10 3:27 pm
the number of horses = no of tails
no of legs = no of tails + 15
and so if each horse has 4 legs, no of horses = (no of legs) / 4
so let x = no of horses
x = (x + 15) / 4
4x = x + 15
3x = 15
x = 5
there are 5 horses
no of legs = no of tails + 15
and so if each horse has 4 legs, no of horses = (no of legs) / 4
so let x = no of horses
x = (x + 15) / 4
4x = x + 15
3x = 15
x = 5
there are 5 horses
參考: my head ;)
2008-08-10 12:16 pm
4n-n=15
3n=15
n = 5
3n=15
n = 5
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