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maths題1題
2008-08-09 9:54 pm
回答 (1)
2008-08-09 10:10 pm
✔ 最佳答案
-(x^2+3)-[(x+m)-(5-x-2x^2)]= -x^2 - 3 - [x + m - 5 + x + 2x^2]
= -x^2 - 3 - [2x^2 + 2x + m - 5]
= -x^2 - 3 - 2x^2 - 2x - m + 5
常數項為6,即沒x的項
-3 - m + 5 = 6
m = -4
收錄日期: 2021-04-13 15:56:17
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080809000051KK01213