How to do this ???? F.3 MATH QU

2008-08-07 10:45 pm
how to do this ????????????????????

(3^(n+1)-3^(n-1))/2*3^n
更新1:

I dont understand ! plz asked easily

回答 (2)

2008-08-08 5:23 am
I dont understand ! plz asked easily
2008-08-07 11:15 pm
(3^(n+1)-3^(n-1))/(2*3^n)
=3^(n-1)*(3^2-1)/2*3^n
=3^(n-1-n)*8/2
=4/3


收錄日期: 2021-04-22 00:37:05
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080807000051KK01580

檢視 Wayback Machine 備份