問題係 3Y^2 + (開方6) Y - 4 = 0.
第2項個y冇開方的...
答案係
2根6 over 3 or 根6 over 3
A- MATHS ...教教我.
2008-08-07 12:48 am
回答 (2)
2008-08-14 4:21 am
2008-08-07 1:07 am
it can be solved by using QUADRATIC FORMULA
3Y^2 + (開方6) Y - 4 = 0
Y={- (開方6)+開方[(開方6)^2-(4)(3)(-4)]}/6
OR{- (開方6)-開方[(開方6)^2-(4)(3)(-4)]}/6
Y=[-(開方6)+3(開方6)]/6
OR[-(開方6)-3(開方6)]/6
Y= -2(開方6)/3
OR(開方6)/3
3Y^2 + (開方6) Y - 4 = 0
Y={- (開方6)+開方[(開方6)^2-(4)(3)(-4)]}/6
OR{- (開方6)-開方[(開方6)^2-(4)(3)(-4)]}/6
Y=[-(開方6)+3(開方6)]/6
OR[-(開方6)-3(開方6)]/6
Y= -2(開方6)/3
OR(開方6)/3
參考: me~
收錄日期: 2021-04-22 00:36:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080806000051KK02184