algebra 2 problem I don't understand?

.....1
---------
(³√-64)²

1
------
(-4)²

1/16

(-64)^(-2/3)
= ³√(-64^-2)
= ³√(1/-64^2)
= ³√(1/4096)
= ³√(1/16 * 1/16 * 1/16)
= 1/16

(-64)^(-2/3)

make positive power
(1/64)(2/3)

(1/4)^3*(2/3)

(1/4)^2

1/16


thanx

{ - 64 }^-2/3 =[{-4}^3]^-2/3 ={ -4}^-2= 1/-4^2=1/16=1/(4)^2

(-64)^(-2/3)

cube root -64 which is -4

(-4)^(-2)

square -4 which is 16

16^(-1)

raising to a negative power puts it in the denominator of the fraction

1/16

You can do all of this in one step but I broke it up this way so you can see what is happening.