multiply: (v 1/4)(v 1/3)

Is it
(v + 1/4) (v + 1/3)
= [(4v + 1)/4][(3v + 1)/3]
= [(4v + 1)(3v + 1)/12]
= [12v² + 7v + 1]/12

or
Is it
[(v + 1)/4] [(v + 1)/3]
= [(v + 1)(v + 1)/12]
= [(v + 1)²/12]
= [(v² + 2v + 1)/12]
--------

v² + v/3 + v/4 + 1/12
v + 7v/12 + 1/12

(v+1/4)(v+1/3)
v^2+(1/3v)+(1/4v)+1/12
v^2+7/12v+1/12

(v + 1/4)(v + 1/3)
= v*v + 1/4*v + v*1/3 + 1/4*1/3
= v^2 + v/4 + v/3 + 1/12
= v^2 + 3v/12 + 4v/12 + 1/12
= v^2 + (3v + 4v + 1)/12
= v^2 + (7v + 1)/12