中3 數學..thx!!

2008-08-03 5:02 am
(2x^2y)^3/x^10y

6^2x-3=36^x+1

4^2x=1/16

5^x+1-5^x-100=0

pa-pb-qa+qb

18z^2-12z+2

3x^4+6x^2+3


thx!!

回答 (2)

2008-08-03 7:36 am
✔ 最佳答案
(1)
(2x^2y)^3/x^10y
= 8y^2 / x^4
(2)
6^(2x-3) = 36^(x+1)
6^(2x-3) = 6^2(x+1)
compare the index
2x-3 = 2(x+1)
Contraction (please check your question again)
(3)
4^2x = 1/16
2^4x = 2^(-4)
compare the index
4x = -4
x = -1
(4)
5^(x+1) - 5^x -100 = 0
5(5^x) - 5^x = 100
4(5^x) = 100
5^x = 25
5^x = 5^2
x = 2
(5)
pa-pb - qa+qb
= p(a-b) -q(a-b)
= (p-q)(a-b)
(6)
18z^2 - 12z + 2
=2(9z^2 - 6z + 1)
=2 (3x - 1)^2
(7)
3x^4 +6x^2 + 3
=3(x^4+2x^2 +1)
=3(x^2+1)^2
2008-08-03 7:13 am
解方程同因式分解?!


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