Laws of indices

2008-08-02 6:44 pm
solve these equations

5^k+5^(k+1)=0.24

5*3^(y-1)+3^(y+2)-6^-2/2^7=0
更新1:

sor, 應該是 5^k+5^(k-1)=0.24

更新2:

How to use "log"? How can I put "k", "x".... in 計算機?

更新3:

how can I put "=" in計算機

更新4:

my 計算機 is fx-3650P, Please teach me!! only puting in "="!!

回答 (1)

2008-08-02 7:02 pm
✔ 最佳答案
1.
5^k+5^(k+1)=0.24
5^k+5(5^k)=0.24
6(5^k)=0.24
5^k=0.04
k log 5 = log 0.04
k=-2

2008-08-02 11:11:36 補充:
2.
5*3^(y-1)+3^(y+2)-6^-2/2^7=0
(5/3)(3^y)+9(3^y)-1/4068=0
(32/3)(3^y)=1/4608
3^y=1/49152
y log 3=log(1/49152)
y=-9.83(3SIG.FIG)

我懷疑你打錯題
因為通常都係整數黎

2008-08-02 11:18:45 補充:
1.
5^k+5^(k-1)=0.24
5^k+(1/5)(5^k)=0.24
(6/5)(5^k)=0.24
5^k=0.2
k log 5 = log 0.2
k=-1

計算機上有個掣寫明log..你可以照直按
另外第二樣野係部部機唔同好難答你
你自己睇說明書/上mathdb
會有教

2008-08-02 11:21:12 補充:
呢d係移項的數學問題
係最後答案先要用計算機
中間步驟唔洗輸入"="

2008-08-04 17:39:48 補充:
= 係 "EXE"
參考: ME, me, ok~, 我都用fx3650p


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