6x2 24x = 2x2 - 36

6x² + 24x = 2x² - 36 ... add 36 and subtract 2x² (both sides)
4x² + 24x + 36 = 0 ... factor out the 4
4(x² + 6x + 9) = 0 ... factor the quadratic
4(x + 3)² = 0
x + 3 = 0
x = -3

1st factor is 4:
6x² + 24x = 2x² - 36
4x² + 24x = - 36
4(x² + 6x) = - 9

x² + 6x = - 9
x² + 3x = - 9 + 3²
x² + 3x = - 9 + 9
(x + 3x)² = 0
x + 3 = 0

2nd factor:
= x + 3

3rd factor:
= (x² + 6x + 9)/(x + 3)
= x + 3

Value of x:
x = - 3

Answer: x = - 3; factors: (4)(x + 3)(x + 3) or 4(x + 3)²

Proof (x = - 3):
6(- 3²) + 24(- 3) = 2(- 3²) - 36
6(9) - 72 = 2(9) - 36
54 - 72 = 18 - 36
- 18 = - 18

6x²+24x = 2x²-36
4x²+24x+36 = 0
(2x+6)(2x+6) = 0
x = -3

6x^2 + 24x = 2x^2 - 36
6x^2 - 2x^2 + 24x + 36 = 0
4x^2 + 24x + 36 = 0
(4x^2 + 24x + 36)/4 = 0/4
x^2 + 6x + 9 = 0
x^2 + 3x + 3x + 9 = 0
(x^2 + 3x) + (3x + 9) = 0
x(x + 3) + 3(x + 3) = 0
(x + 3)(x + 3) = 0

x + 3 = 0
x = -3

∴ x = -3

Introducing a + sign (but I am but guessing) :-

6x² + 24x = 2x² - 36
4x² + 24x + 36 = 0
x² + 6x + 9 = 0
(x + 3)(x + 3) = 0
x = - 3

6x^2+24x=2x^2-36

4x^2+24x+36=0

(2x+6)^2=0

x=-3

how come there's no sign in between 6x2 and 24x?