f(x)=x^x f'(x) = ?

2008-08-02 6:41 am
如題= =
d
__ (x^x) = ?
dx

回答 (2)

2008-08-02 6:59 am
✔ 最佳答案
Let y=x^x
lny=xlnx
d(lny)/dx=x(1/x)+lnx=lnx+1
(1/y)y'=lnx+1
y'=y(lnx+1)
y'=x^x(lnx+1)
so f'(x)=x^x(lnx+1) [f(x)=x^x]
2008-08-02 6:44 am
可能冇呢


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