f(x)=x^x f'(x) = ?

Let y=x^x
lny=xlnx
d(lny)/dx=x(1/x)+lnx=lnx+1
(1/y)y'=lnx+1
y'=y(lnx+1)
y'=x^x(lnx+1)
so f'(x)=x^x(lnx+1) [f(x)=x^x]

可能冇呢