8x + 8y = 40 8x = 40 – 8y x = (40/eight) – (8y/eight) x = 5 – y Double examine that x = 5 – y by plugging it returned into your unique equation eight(5 – y) + 8y = 40 40 – 8y + 8y = 40 40 = 40 Now you realize it particularly is actual, so plug x = 5 - y into the 2nd equation -4x + y = 20 -4(5 – y) + y = 20 -20 + 4y + y = 20 -20 + 5y = 20 5y = 40 y = eight Now plug y = eight into your equation -4x + y = 20 -4x + eight = 20 -4x = 12 x = -3 i desire that facilitates!
There is a grammatical problem with the question. If it should read:
4x+8y = 40-8x
y = 22
then we can simply insert the second equation into the first to get:
4x + 176 = 40-8x, or 12x = - 136, or x = 11.3333