Factor 5y – 21x + 3xy – 35 completely??

5y-21x+3xy-35

Rearrange the equation so the factors are more obvious,

=5y-35+3xy-21x
=5(y-7)+3x(y-7)

The factor (y-7) allows us to combine 5 and 3x,

=(5+3x)(y-7)

(5y - 35) + (3xy - 21x)
5(y - 7) + 3x(y - 7)
(y - 7)(3x+ 5)

5y – 21x + 3xy – 35
Rearrange this eq. as
-21x - 35 + 3xy + 5y
= (-21x - 35) + (3xy + 5y) (Grouping this eq.)
= -7(3x + 5) + y(3x + 5)
= (3x + 5) (y - 7)

=5(y-7)+3x(y-7)
=(5+3x)(y-7)

5y - 21x + 3xy - 35
= 3xy - 21x + 5y - 35
= (3xy - 21x) + (5y - 35)
= 3x(y - 7) + 5(y - 7)
= (y - 7)(3x + 5)

:)

5y - 21x + 3xy - 35
= 3xy - 21x + 5y - 35
= (3xy - 21x) + (5y - 35)
= 3x(y - 7) + 5(y - 7)
= (y - 7)(3x + 5)