(3x^2 + 2x - 5) + (5x^2 - 4x + 6)
Step 1: Combine 3x^2 and 5x^2 together since they both are to the power of two. Since there is a plus sign between the two terms and they are both positive just add.
Step 2: The coefficient of 2 in the first term is x. In the second term the coefficient of -4 is also x. Therefore we will combine these terms. 2x + -4x. Same as 2x - 4x, which equals -2x.
Step 3: The coefficient of -5 and 6 is 1. So combine them. -5 + 6, or 6 -5. This equals 1. So your answer should like this
ANSWER: 8x^2 - 2x + 1
(8x^2-2x+1) thats the main solution, if you need the roots you have to separate it (8x-4) (8x+2) and u have to reduce to (2x-4) and (4x+1) so you get the roots 2 and -1/4 thats the full solution
參考: Took math B got a 95 on the New York math B regents
we can only add like terms together, so x^2 with x^2, x with x and a number with a number
thus,
(3x^2 + 2x – 5) + (5x^2 – 4x + 6) =
3x^2 + 5x^2 + 2x – 4x - 5 + 6 =
8x^2 -2x -1