linear equations in two unknows

2008-07-30 11:42 pm
solve the following systems of equstions by the method of substitution
a+3a=18 16w=5-4s
3a+5b=24 3s-8=8w+7

solve the following systems of equstions by the method of elimination
5x-2y=6 6x-(y-4)/3 = 10
3x+2y=10 y+(3x-7)/4 =1

回答 (4)

2008-08-02 8:19 pm
✔ 最佳答案
1.第一條係唔係嫁,a,b,w,s四個?唔明.
今晚先睇你88
2008-08-05 11:40 pm
rickyricky2828 well done
2008-08-05 4:13 am
我係到諗緊第一條係唔係a+3b=18就唔係a+3a=18
當個條問題係
     (a) a+3b=18
       3a+5b=34
咁樣就可以叫做a=3 b=5
當然...如果真係a+3a=18我真係諗唔到
如果係咁(b)題應該係咁...岩唔岩
     (b) 16w=5-4s
3s-8=8w+7
我只係...發表現見...非回答者...希望我既意見幫到其他回答你問題既人
2008-07-31 7:04 pm
Substitution and Elimination 入面應該各有兩條數, 你咁排位, Subsititution 仲好 d, 英文字分到, 但係 elimination 就好難分, 因為大家都係 x, y, 唔知打直叫一題, 定打橫叫一題 wor


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