9t^2 + 9t
__________
36t^2 + 81t
(supposed to be a fraction)
Simplyify by removing factors of 1?
2008-07-29 3:51 pm
回答 (3)
2008-07-29 4:00 pm
✔ 最佳答案
Factor both the numerator and denominator9t(t+1) / 9t(4t + 9)
Divide both numerator and denominator by 9t
(t+1)/(4t+9) where t is not 0
You need the "t is not 0" comment, because if t is 0, the initial fraction is undefined (dividing by 0 is a bad idea:).
2008-07-29 3:58 pm
(9t^2 + 9t)/(36t^2 + 81t)
= 9(t^2 + t)/9(4t^2 + 9t)
= 9t(t + 1)/9t(4t + 9) (cancel out 9t)
= (t + 1)/(4t + 9)
= 9(t^2 + t)/9(4t^2 + 9t)
= 9t(t + 1)/9t(4t + 9) (cancel out 9t)
= (t + 1)/(4t + 9)
2008-07-29 3:55 pm
divide numerator and denominator by 9t
(t+1) / (4t+9)
(t+1) / (4t+9)
收錄日期: 2021-05-01 10:55:00
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080729075137AAwXb65