Solve. The solution is x =?
回答 (5)
2008-07-29 4:20 pm
✔ 最佳答案
This equation is of form ax^2+bx+c=0a = 1 b = 6 c = -4
x=[-b+/-sqrt(b^2-4ac)]/2a]
x=[-6 +/-sqrt(6^2-4(1)(-4)]/(2)(1)
discriminant is b^2-4ac =52
x=[-6 +√(52)] / (2)(1)
x=[-6 -√(52)] / (2)(1)
x=[-6+7.211102550927978] / 2
x=[-6-7.211102550927978] / 2
The roots are 0.6056 and -6.6056
2008-07-30 12:04 am
x = [ - 6 ± â (36 + 16) ] / 2
x = [ - 6 ± â (52) ] / 2
x = [ - 6 ± 2â13 ] / 2
x = - 3 ± â13
x = [ - 6 ± â (52) ] / 2
x = [ - 6 ± 2â13 ] / 2
x = - 3 ± â13
2008-07-29 10:58 pm
I'll give you all of the steps and use the quadratic formula:
x = [ -6 pm sqrt(36 - 16)] / 2 where pm is plus or minus
= [ -6 pm sqrt(20)] / 2
= [ - 6 pm sqrt(4 * 5)] / 2 where * is the multiplication symbol
= [ -6 pm (sqrt(4) * sqrt(5)] / 2
= [ -6 pm (2 * sqrt(5))] / 2 and dividing by two
= -3 pm sqrt(5)
x = [ -6 pm sqrt(36 - 16)] / 2 where pm is plus or minus
= [ -6 pm sqrt(20)] / 2
= [ - 6 pm sqrt(4 * 5)] / 2 where * is the multiplication symbol
= [ -6 pm (sqrt(4) * sqrt(5)] / 2
= [ -6 pm (2 * sqrt(5))] / 2 and dividing by two
= -3 pm sqrt(5)
2008-07-29 10:56 pm
USE FORMULA
x= [-6+-SQrt{6^2- 4*1*(-4)]/2*1= [6+-V{52}]/2
OR x =( 6+-2V13)/2 ANS
x= [-6+-SQrt{6^2- 4*1*(-4)]/2*1= [6+-V{52}]/2
OR x =( 6+-2V13)/2 ANS
2008-07-29 10:55 pm
x^2 + 6x - 4 = 0
x = [-b 屉(b^2 - 4ac)]/2a
a = 1
b = 6
c = -4
x = [-6 屉(36 + 16)]/2
x = [-6 屉52]/2
x = [-6 ±7.21]/2 (approx.)
x = [-6 + 7.21]/2
x = 1.21/2
x = 0.605
x = [-6 - 7.21]/2
x = -13.21/2
x = -6.605
â´ x = -6.605 , 0.605 (approx.)
x = [-b 屉(b^2 - 4ac)]/2a
a = 1
b = 6
c = -4
x = [-6 屉(36 + 16)]/2
x = [-6 屉52]/2
x = [-6 ±7.21]/2 (approx.)
x = [-6 + 7.21]/2
x = 1.21/2
x = 0.605
x = [-6 - 7.21]/2
x = -13.21/2
x = -6.605
â´ x = -6.605 , 0.605 (approx.)
參考: Square Root Calculator
http://www.math.com/students/calculators/source/square-root.htm
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