Solve. The solution is x =?

This equation is of form ax^2+bx+c=0
a = 1 b = 6 c = -4
x=[-b+/-sqrt(b^2-4ac)]/2a]
x=[-6 +/-sqrt(6^2-4(1)(-4)]/(2)(1)
discriminant is b^2-4ac =52
x=[-6 +√(52)] / (2)(1)
x=[-6 -√(52)] / (2)(1)
x=[-6+7.211102550927978] / 2
x=[-6-7.211102550927978] / 2
The roots are 0.6056 and -6.6056

x = [ - 6 ± √ (36 + 16) ] / 2
x = [ - 6 ± √ (52) ] / 2
x = [ - 6 ± 2√13 ] / 2
x = - 3 ± √13

I'll give you all of the steps and use the quadratic formula:

x = [ -6 pm sqrt(36 - 16)] / 2 where pm is plus or minus

= [ -6 pm sqrt(20)] / 2

= [ - 6 pm sqrt(4 * 5)] / 2 where * is the multiplication symbol

= [ -6 pm (sqrt(4) * sqrt(5)] / 2

= [ -6 pm (2 * sqrt(5))] / 2 and dividing by two

= -3 pm sqrt(5)

USE FORMULA
x= [-6+-SQrt{6^2- 4*1*(-4)]/2*1= [6+-V{52}]/2
OR x =( 6+-2V13)/2 ANS

x^2 + 6x - 4 = 0
x = [-b ±√(b^2 - 4ac)]/2a

a = 1
b = 6
c = -4

x = [-6 ±√(36 + 16)]/2
x = [-6 ±√52]/2
x = [-6 ±7.21]/2 (approx.)

x = [-6 + 7.21]/2
x = 1.21/2
x = 0.605

x = [-6 - 7.21]/2
x = -13.21/2
x = -6.605

∴ x = -6.605 , 0.605 (approx.)