解方程(-3x-1)(x+1)=3x,並以根式表示答案
化簡(x^2-5)(x+4)-(2x^2-9),並將各項按x的降幕序排列
已知f(x)=x^3+ax^2-7x+6-7x+6及g(x)=x^3+2x^2-5x-3b
當f(x)除以x+1,餘數是12;而g(x)可被x+3整除
(a)求a和b的值
(b)證明x+3是f(3)的因式
化簡下列各式,以正指數表示答案
(a)(a^2b^-1)^3/a^-2b
(b)√[x(^3√x)]
四條中四的數
2008-07-29 8:40 pm
回答 (3)
2008-08-04 2:33 am
✔ 最佳答案
f(x)方程應該打錯!2008-08-03 18:33:22 補充：
As follow AS~~~~
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2008-07-29 11:27 pm
(a^2 b^-1)^3 / a^-2 b
= a^6 b^-3 / a^-2 b
= a^8 / b^4
√[x(^3√x)]
= √{x[x^(1/3)]}
= √x^(1 + 1/3)
= √x^(4/3)
= [x^(4/3)]^(1/2)
= x^(2/3)
= a^6 b^-3 / a^-2 b
= a^8 / b^4
√[x(^3√x)]
= √{x[x^(1/3)]}
= √x^(1 + 1/3)
= √x^(4/3)
= [x^(4/3)]^(1/2)
= x^(2/3)
2008-07-29 9:05 pm
化簡(x^2-5)(x 4)-(2x^2-9),並將各項按x的降幕序排列
= x^3 2x^2 - 5x - 29
2008-07-29 13:06:03 補充：
化簡(x^2-5)(x+4)-(2x^2-9),並將各項按x的降幕序排列
= x^3+2x^2-5x-29
= x^3 2x^2 - 5x - 29
2008-07-29 13:06:03 補充：
化簡(x^2-5)(x+4)-(2x^2-9),並將各項按x的降幕序排列
= x^3+2x^2-5x-29
參考: 我
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