{(3^-2)(2^-3)}^-1 =?

[ (1/9) (1/8) ] ^(-1)

[ 1 / 72 ] ^(-1)

72

You produced a very clear question by using brackets----well done !

{(3^-2)(2^-3)}^-1
=1/((1/3)^2*(1/2)^3)
=1/((1/9)*(1/8))
=1/(1/72)
=72

[(3^-2)(2^-3)]^-1
= 1/[(3^-2)(2^-3)]
= 1/[(1/9)(1/8)]
= 1/[1/72]
= 1[72/1]
= 72/1
= 72

{(3^-2)(2^-3)}^-1 =?
=> {[1 / (3^2) ][1 / (2^3) ]}^-1
=> { (1/9)(1/8) }^-1
=> (1/72)^-1
=> 72^1=72
The answer is 72

Reciprocaling It becomes
[ {(1/3)^2} {( 1/2)^3 ]^-1
=> [ (1/9)(1/8)] ^-1
=> [ 1/72 ]^-1
=> 72 answer

{(3^-2)(2^-3)}^-1
= 1/[(3^-2)(2^-3)]
= 1/[(1/3^2)(1/2^3)]
= 1/[(1/9)(1/8)]
= 1/(1/72)
= 72

Hi,

{(3^-2)(2^-3)}^-1 =

{(3²)(2³)} = (9)(8) = 72 <==ANSWER

I hope that helps!! :-)