4c/3c-6 + 8c/6c-12?

I agree with Jon P. Rephrase pls.

4c/(3c - 6) + 8c/(6c - 12)
= 2(4c)/2(3c - 6) + 8c/(6c - 12)
= 8c/(6c - 12) + 8c/(6c - 12)
= (8c + 8c)/(6c - 12)
= 16c/(6c - 12)
= 2(8c)/6(c - 2)
= [2/6][8c/(c - 2)]
= [1/3][8c/(c - 2]
= 8c/3(c - 2)

Question is INCORRECT.
Should be shown as :-
4c / (3c - 6) + 8c / (6c - 12)
4c / [ 3 (c - 2) ] + 8c / [ 6 (c - 2) ]
(8c + 8c) / [ 6c (c - 2) ]
8(c + 1) / [ 6c (c - 2) ]
4(c + 1) / 3c(c - 2)

fix question

is it 4c/(3c-6) + 8c/(6c-12)??

or 4c/3c - 6 + 8c/6c - 12??

4/3+8/6=( after so many steps) 8/3
then

-6-12 is left which equals -18
then

-18/1+8/3= ( after steps) -46/3 also known as -15and 1/3
your answer u need is
-15 and 1/3 it's a mixed fraction