[a^4b^-2/a^-3b]^3?
回答 (4)
2008-07-26 4:31 pm
(a^4b^-2/a^-3b)^3
= a^(4 * 3)b^(-2 * 3)/a^(-3 * 3)b^3
= a^12b^-6/a^-9b^3
= (a^12/a^-9)(b^-6/b^3)
= a^(12 + 9)b^(-6 - 3)
= a^21b^-9
= a^21(1/b^9)
= a^21/b^9
= a^(4 * 3)b^(-2 * 3)/a^(-3 * 3)b^3
= a^12b^-6/a^-9b^3
= (a^12/a^-9)(b^-6/b^3)
= a^(12 + 9)b^(-6 - 3)
= a^21b^-9
= a^21(1/b^9)
= a^21/b^9
2008-07-26 2:49 pm
a^12 b^(- 6)
---------------------
a^(- 9) b³
a^21
--------
b^9
---------------------
a^(- 9) b³
a^21
--------
b^9
2008-07-26 1:26 pm
index laws.
multiply all powers by 3.
= (a^12)(b^-6) / (a^-9)(b^3)
= [a^(12 - -9)] [(b^(-6 -3)]
= (a^21)(b^-9)
multiply all powers by 3.
= (a^12)(b^-6) / (a^-9)(b^3)
= [a^(12 - -9)] [(b^(-6 -3)]
= (a^21)(b^-9)
收錄日期: 2021-05-01 10:53:18
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