find the two consecutive even number whose product is 48.?

n(n + 2) = 48
n² + 2n - 48 = 0
(n + 8)(n - 6) = 0
n = 6 or -8
so 6 and 8
or
-8 and -6

NOTE:
Your question says: find "THE" 2 consec...
There are 2 correct pairs:
-8 and -6 are two consecutive even number whose product is 48
6 and 8 are also two consecutive even number whose product is 48

xy = 48 (solve by using subsitution)
x - y = 2

x - y = 2
x = 2 + y

xy = 48
(2 + y)y = 48
2y + y^2 = 48
y^2 + 2y - 48 = 0
y^2 + 8y - 6y - 48 = 0
(y^2 + 8y) - (6y + 48) = 0
y(y + 8) - 6(y + 8) = 0
(y + 8)(y - 6) = 0

y + 8 = 0
y = -8

y - 6 = 0
y = 6

x - y = 2
x - (-8) = 2
x + 8 = 2
x = 2 - 8
x = -6

x - y = 2
x - 6 = 2
x = 2 + 6
x = 8

∴ (x = -6 , y = -8) , (x = 6 , y = 8)

6 and 8.

( 2x ) (2x + 2) = 48
4x² + 4x = 48
x² + x - 12 = 0
(x + 4)(x - 3) = 0
Accept x = 3

Nos. are 6 and 8

a(a+2)=48
a^2+2a-48=0
a=[-2+-sqrt(4-4*(-48))]/2
a=-1+-7
a=-8
a=6

6 x 8

Let x = the first number and x+2 = the second number.

Now use the formula:
x(x+2)=48
x^2+2x-48=0
(x-6)(x+8)=0

We disregard the negative sign and have:

6 & 8, where they are two consecutive even numbers whose product is 48.

Have a nice day!

6 and 8

6 and 8 are consecutive even numbers (aka they are rightnext to each other)

6 x 8 = 48

so there the answer is 6 and 8

is it 6 and 8