(3x^4 + x2 + 5.5x + 8) - (x4 + x2 + 4x + 4)?

1) Distribute the negative through the second have of your equation = 3x^4+x^2+5.5x+8-x^4-x^2-4x-4
2) Rearrange similar variables = 3x^4-x^4+x^2-x^2+5.5x-4x+8-4
3) Add each similar variable together
~ 3x^4 - x^4 = 2x^4
~ x^2 - x^2 = 0
~ 5.5x - 4x = 1.5x
~ 8-4 = 4
4) Get answer = 2x^4 + 1.5x + 4

First, you desire to subtract 4x and four to get each thing on one area. x² + x -12 = 0 for many problems like this, you will ought to apply the quadratic formulation, or in case you have a graphing calculator, plug the two facets of the equation right into a graph and locate the place they intersect (2d + hint -> Intersect), yet as a consequence the equation factors authentic. (x + 4)(x - 3) = 0 certainly one of the two contraptions of parentheses has to equivalent 0 for the equation to equivalent 0, so your 2 ideas are at x = 3 and -4.

2 x^4 + 1.5 x + 4

(3x^4 + x^2 + 5.5x + 8) - (x^4 + x^2 + 4x + 4)
= 3x^4 + x^2 + 5.5x + 8 - x^4 - x^2 - 4x - 4
= 3x^4 - x^4 + x^2 - x^2 + 5.5x - 4x + 8 - 4
= 2x^4 + 1.5x + 4

(3x^4 + x2 + 5.5x + 8) + (x4 - x2 - 4x - 4)

3x4 + x2 + 5.5x + 8 + (x4 - x2 - 4x - 4)

3x4 + 5.5x + 8 + (x4 - 4x - 4)

3x4 + 1.5x + 8 + x4 - 4

4x4 + 1.5x + 4

The way you figure this one out is to distribute a negative 1 to the second polynomial, and then you get

3x^4 + x^2 +5.5x + 8 - x^4 - x^2 - 4x - 4

Now it is just a simple matter of combining like terms. This is what you wind up with:

2x^4 + 1.5x + 4

just subtract the common terms:
3x^4 - x^4 + x^2 - x^2 + 5.5x - 4x + 8 - 4
= 2x^4 + 1.5x + 4

2x^4 +1.5x + 4