x^2 + x – 30 = 0.?

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(x+6)(x-5)=0
x=5,-6

(x+6)(x-5)=0
x = -6, or 5 (B)

(x-5)(x+6)=0
x = 5 or x= -6.

So, the answer to your question is (B).

x^2+x-30=0

x^2+x=30

x(x+1)=30

30 = -6 * -5 and 30=+6*+5

so x=-6 and x=+5

Question Number 1 :
For this equation x^2 + x - 30 = 0 , answer the following questions :
A. Find the roots using Quadratic Formula !
B. Use factorization to find the root of the equation !
C. Use completing the square to find the root of the equation !

Answer Number 1 :
The equation x^2 + x - 30 = 0 is already in a*x^2+b*x+c=0 form.
By matching the constant position, we can derive that the value of a = 1, b = 1, c = -30.

1A. Find the roots using Quadratic Formula !
Use the formula,
x1 = (-b+sqrt(b^2-4*a*c))/(2*a) and x2 = (-b-sqrt(b^2-4*a*c))/(2*a)
We had know that a = 1, b = 1 and c = -30,
we need to subtitute a,b,c in the abc formula, with thos values.
So we get x1 = (-(1) + sqrt( (1)^2 - 4 * (1)*(-30)))/(2*1) and x2 = (-(1) - sqrt( (1)^2 - 4 * (1)*(-30)))/(2*1)
Which can be turned into x1 = ( -1 + sqrt( 1+120))/(2) and x2 = ( -1 - sqrt( 1+120))/(2)
Which can be turned into x1 = ( -1 + sqrt( 121))/(2) and x2 = ( -1 - sqrt( 121))/(2)
It imply that x1 = ( -1 + 11 )/(2) and x2 = ( -1 - 11 )/(2)
We get following answers x1 = 5 and x2 = -6

1B. Use factorization to find the root of the equation !
x^2 + x - 30 = 0
( x - 5 ) * ( x + 6 ) = 0
We get following answers x1 = 5 and x2 = -6

1C. Use completing the square to find the root of the equation !
x^2 + x - 30 = 0 ,divide both side with 1
By doing so we get x^2 + x - 30 = 0 ,
And the coefficient of x is 1
We have to use the fact that ( x + q )^2 = x^2 + 2*q*x + q^2 , and assume that q = 1/2 = 0.5
Which means we can turn the equation into x^2 + x + 0.25 - 30.25 = 0
And it is the same with ( x + 0.5 )^2 - 30.25 = 0
So we will get (( x + 0.5 ) - 5.5 ) * (( x + 0.5 ) + 5.5 ) = 0
And it is the same with ( x + 0.5 - 5.5 ) * ( x + 0.5 + 5.5 ) = 0
And it is the same with ( x - 5 ) * ( x + 6 ) = 0
We get following answers x1 = 5 and x2 = -6

(x + 6)(x - 5) = 0
x = - 6 , x = 5
OPTION B

x^2 + x - 30 = 0
x^2 + 6x - 5x - 30 = 0
(x^2 + 6x) - (5x + 30) = 0
x(x + 6) - 5(x + 6) = 0
(x + 6)(x - 5) = 0

x + 6 = 0
x = -6

x - 5 = 0
x = 5

∴ x = -6 , 5
(answer B)

ok all of thse people on yhoo seriously havent learnt their zero property work!!!!

(x+6)(x-5)=0

now by the ZERO PRoperty either x+6=0 or x-5=0
so x=-6 or x = +5