how do I find the factor: x2(second) - 7x+12?

Question Number 1 :
For this equation x^2 - 7*x + 12 = 0 , answer the following questions :
A. Use factorization to find the root of the equation !

Answer Number 1 :
The equation x^2 - 7*x + 12 = 0 is already in a*x^2+b*x+c=0 form.
By matching the constant position, we can derive that the value of a = 1, b = -7, c = 12.

1A. Use factorization to find the root of the equation !
x^2 - 7*x + 12 = 0
x^2 - 3*x - 4*x + 12 = 0
x( x - 3 ) - 5( x - 3 ) = 0
( x - 4 ) * ( x - 3 ) = 0
So we got the answers as x1 = 4 and x2 = 3

x^2 - 7x + 12
= x^2 - 3x - 4x + 12
= (x^2 - 3x) - (4x - 12)
= x(x - 3) - 4(x - 3)
= (x - 3)(x - 4)

x^2-7x+12
x^2-4x-3x+12
x(x-4)-3(x-4)
(x-4)(x-3)

find two numbers whose product is +12 ans whose sum is -7.
The numbers are -4 and -3
Write -7 as -4-3

x² – 7x + 12
= x² – 3x – 4x + 12
= x(x – 3) – 4(x – 4)
= (x – 3)(x – 4)
-------

(x-4)(x-3)

(x-4)(x-3)