how doyou solve -4x2(3x2 - x + 1)?

2008-07-21 2:12 pm

回答 (4)

2008-07-21 2:40 pm
✔ 最佳答案
– 4x²(3x² – x + 1)
= (– 4x²)(3x²) – (– 4x²)(x) + 1(– 4x²)
= – 12x^4 + 4x³ – 4x²
---------
2008-07-22 2:49 am
What do you mean by "Solve?"

There is no = sign.

Multiplying out gives :-

- 12 x^4 + 4x³ - 4x²
2008-07-22 12:08 am
-4x^2(3x^2 - x + 1)
= -4x^2*3x^2 + 4x^2*x - 4x^2*1
= -12x^(2 + 2) + 4x^(2 + 1) - 4x^2
= -12x^4 + 4x^3 - 4x^2
2008-07-21 9:26 pm
You don't have enough information to solve this equation for x. The original expression has had the -4x^2 term factored from it.

You can return the expression to its original form.

Multiply each term within the parantheses by the -4x^2 term:

(-4x^2 * 3x^2) + (4x^2 * x) - 4x^2

-12x^4 + 4x^3 - 4x^2


收錄日期: 2021-05-01 10:52:03
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080721061239AAI9nza

檢視 Wayback Machine 備份