我有三條數學題唔識做,關於指數及數系,百分數 希望有人幫下我!!!!!!

2008-07-21 7:01 am
1) 求兩個可能的三位十進數,它們均能轉換為一個八位二進氀及一個兩位十六進數。
2)已知一個二進數轉換為十進數後可被6及8整除。求該二進數的兩個可能值。
3)某店提高一手錶的標價後,再提供折扣以吸引顧客購買。若該手錶的成本為$860,試寫出兩種方法,先以一特定百分數提高該手錶的標價,然後提供一折扣百分數,使得售出該手錶的盈利百分數剛好為35%。


希望有人幫下我!!!!!!

回答 (1)

2008-07-21 6:05 pm
✔ 最佳答案
1)For 1 to 8 digits binary numbers, it is from 0 to 256.
For 1 to 2 digits hexadecimal numbers, it is from 0 to 255.
So the possible 8 digits binary number and 2 digits hexadecimal numbers are 192 and 128.(Binary number are 11000000 and 10000000. Hexadecimal numbers are C0 and 80.
2)The LCM of 6 and 8 is 24. So the possible binary numbers are 11000 (=24) and 110000(=48).
3)Let the % mark -up = x and % discount = y.
The marked price = 860(1+x).
Selling price = 860(1+x)(1-y).
Therefore, % profit = [860(1+x)(1-y) - 860]/860 = (1+x)(1-y) - 1.
So (1+x)(1-y) - 1 = 0.35
(1+x)(1-y) = 1.35.
For x = 0.8, y = 1 - 1.35/1.8 = 0.25.
For x = 0.5 y = 1-1.35/1.5 = 0.1.

2008-07-21 10:08:21 補充:
For Q.3, the methods are mark -up 80% and discount 25% or mark-up 50% and discount 10%. The profit % is 35%.


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