5(2x-7)<-8?

Baby, the exercise is realized well, now I am going to complement the exercise explaining clearly, OK? Here we go:

PASS 1:

We multiply 5 with (2x-7) by the distributive, like that law:

10x-35

PASS 2:

We continue with the exercise:

10x-35 <-8

PASS 3:

Now we spend 35 that it is reducing to adding up to another side of the equation:

10x <-8+35

PASS 4:

We add up:

10x <27

PASS 5:

We clear x to obtain the value:

X <27/10
The response is: <27/10, it wants to say, immensely with 27/10, that is represented this way: (∞, 27/10)

I hope that my explanations serve you, bye-bye! =)

5(2x - 7) < - 8
10x - 35 < - 8
10x < 27
x < 27/10
x < 2 7/10

Answer: x < 2 7/10

5(2x - 7) < -8
5*2x - 5*7 < -8
10x - 35 < -8
10x < -8 + 35
10x < 27
x < 27/10 (2.7)

10x - 35 < - 8
10x < 27
x < 27 / 10
x < 2.7
You are correct.

Yes, you do because 10 is being multiplied by x, so in order to isolate x you must divide both sides by 10 to undo it.

5(2x - 7) < -8 (distribute)
10x - 35 < -8 (add 35 to both sides)
10x < 27 (divide both sides by 10)
x < 27/10 or 2.7