exponents????????????????

no, you have to do each variable separately


it's c^15d^21

(c^5d^7)^3
= c^(5 * 3)d^(7 * 3)
= c^15d^21

This is NOT an equation as an equation requires an = sign.

This is an expression.

( c^5 d^7 )³ = c^15 d^21

[[To do this, remember: Exponents, Parentheses, Multiply/ Divide, Add/Subtract]]
First, you must break it up:

(c^5) x (d^3) ^3

Once you do that, you must get rid of one variable. To do that, you have to do this:

[[You can put an imaginary 1 before any variable and it will work]]

(5c) x (d^3) ^3
(5c) x (7d) ^3
(5c - 5c) x (7d - 5c)

Since you subtracted 5 from 5, that cancels out so that now you have:

2d^3

I think you can get it from there. =]

[[6d]]

General principle: (ab) ^ (x) = (a^x) (b^x)
Second principle: (a^m) ^ (n) = (a^(mn)) which means you keep the base and multiply the exponents.
We apply this principle to the above problem.
[(c^5)(d^7)]^3
(c^5) ^3 = c^(5*3) = c^15
(d^7) ^ 3 = d^(7*3) = d^21

So the correct answer is: (c^15)(d^21).

Simplify each term separately:
Think about the equation as:

(c^5)^3 and (d^7)^3

that gives you c^15d^21

Review your rules on purplemath.com

c^15d^21 is your answer.

(c^5d^7)^3 (multiply 5 by 3 and 7 by 3)
c^15d^21 <===ANSWER

Since they aren't the same base, you can't add the exponents.

haha i just got outta doing all this crap from 7th grade i am not about 2 even wanna think about doing another equation