5n-7=33 please solve?

5n-7=33

5n=33-7

5n=40

5n/5=40/5

n=8

5n-7=33
add 7 to 33 = 40
then divide 40 by 5
n = 8

5n-7=33 original equation
5n-7=33
+7 +7 add 7 to eliminate the 7 to leave a variable one
side n a contant* on the other
5n=40 what you end up with
5n=40 divide 5 on both sides to leave a variable and a
/5 /5 contant
n=8 your answer is n=8 after dividing

*a contant is a number in an equation without a variable*

5n-7=33 (you just need to combine the like terms...like
terms means a term that have the characteristic of each other but not exactly same in quantity...so it will become.)

5n=33+7 (and when transposing any number across the equall sign,the numbers' adjacent operaion sign will change,,,example for this is the number above,,from negative ( - ) 7,,it becomes positive ( + ) 7 after crossing the equall sign.....then simplify it)

5n=40 (then divide both sides by 5 for the "n" to be left,,,
take note that we are looking for the value of n
and we can only do it if it is not accompanied
by any number)

5n/5=40/5 (then both 5 in "n" cancells themselves....just perform the indicated operation in simplifying)

n=8 ---------ANSWER


.......>

5n -7 =33
transpose -7

you will get,

5n = 33 + 7

5n = 40

divide both sides by 5

n = 40/5

n =8

n=8

8

5n = 40
n = 8

5n=40 n=40/5=8

5n - 7 = 33
5n = 33 + 7
5n = 40
n = 40/5
n = 8