5(2y-1)=3(y-4)?

5(2y - 1) = 3(y - 4)
-> 10y - 5 = 3y - 12,
-> 10y - 3y = -12 + 5,
-> 7y = -7,
So, y = -1....

5(2y - 1) = 3(y - 4)
10y - 5 = 3y - 12
10y - 3y = 5 - 12
7y = - 7
y = - 1

Answer: y = - 1

Proof:
5(2[- 1] - 1) = 3([- 1] - 4)
5(- 2 - 1) = 3(- 1 - 4)
5(- 3) = 3(- 5)
- 15 = - 15

Breaking out the brackets you will get:
10y-5=3y-12
Bringing the 'y's to the left side and the numbers on the right side, you will get:
10y-3y=-12+5
7y=-7
Hence, y= -1

5(2y-1)=3(y-4)
or10y-5=3y-12
or10y-3y=5-12
or7y= -7
or y= -7/7= -1 ans

10y-5=3y-12
7y=-7
y=-1

5(2y - 1) = 3(y - 4)
5*2y - 5*1 = 3*y - 3*4
10y - 5 = 3y - 12
10y - 3y = 5 - 12
7y = -7
y = -7/7
y = -1

5(2y-1)=3(y-4)
10y-5=3y-12
10y-3y= -12+5
7y= -7
y= -1

10 y - 5 = 3y - 12
7y = - 7
y = - 1

5(2y-1)=3(y-4)
10y-5=3y-12
7y=-7
y=-1

5(2y-1)=3(y-4)
10y-5=3y-12
-3y -3y
_________
7y-5=-12
+5 +5
________
7y=-7
/7 /7
y=-1


Tina