FIRST 1 TO ANSWER CURRECTY* GeTS 10 POINTS!!!?

2008-07-17 5:19 pm
1)
2x + y – 10 = 0
x – y – 4 = 0

x = ___
y = ___




2)
4x – 5y = 3
x = 3 – 1/2y

x = ___
y = ___




3)
3x – 2y – 1 = 0
y = 5x + 4

x = ___
y = ___

回答 (8)

2008-07-17 5:34 pm
✔ 最佳答案
Q.1:
2x+ y = 10
x - y = 4
-------------------[add]

2x+x +y-y = 10+4

=>3x = 14
=>x =14/3

now, FROM x - y = 4
=> 14/3 - y = 4
=> y = 14/3 - 4
=> y = (14 - 12)/3
=> y = 2/3

So, x= 14/3
y= 2/3 <==ANSWER

Q.2:

x = 3 - 1/2 y
=> 2x = 6 - y
=> 2x + y = 6

4x - 5y = 3 ........... x 1
2x + y = 6 ............. x 5

4x - 5y = 3
10x + 5y = 30
------------------------[add]

14x = 33
=> x= 33/14

Now FROM: 2 x 33/14 + y = 6
=> 33/7 + y = 6
=> y = 6 - 33/7
=> y = (42 - 33)/7
=> y = 9/7

So, x = 33/14
y = 9/7 <==ANSWER

Q.3:

3x - 2y = 1 ........ x 1
5x - y = - 4 ......... x (-2)

3x - 2y = 1
- 10x + 2y = 8
-------------------------[add]
- 7x = 9
=> x = - 9/7

now, y = 5(-9/7) + 4
=> y = - 45/7 + 4
=> y = (- 45 + 28)/7
=> y = - 17/7

So, x = -9/7
y = -17/7 <==ANSWER
2008-07-18 1:16 am
1)
2x + y – 10 = 0
x – y – 4 = 0

x = 14/3
y = 2/3

2)
4x – 5y = 3
x = 3 – 1/2y

x = 33/14
y = 9/14

3)
3x – 2y – 1 = 0
y = 5x + 4

x = -9/10
y = -1/2
2008-07-18 12:34 am
1)
2x + y – 10 = 0
2x + y = 10
x – y – 4 = 0
x – y = 4
x = 4 + y

2x + y = 10
2(4 + y) = 10
8 + 2y = 10
y = 1
x = 5

2)
4x – 5y = 3
x = 3 – 1/2y
4(3 – 1/2y) – 5y = 3
12 – 2y – 5y = 3
– 7y = – 9
y = 9/7
x = 3 – 9/14 = 33/14

3)
3x – 2y – 1 = 0
y = 5x + 4
3x – 2(5x + 4) = 1
3x – 10x – 8 = 1
– 7x = 9
x = – 9/7
y = – 45/7 + 4 = – 17/7
--------
2008-07-18 12:32 am
1. x=14/3
y=2/3
2.x=33/14
y=9/7
3. x=-9/7
y=-17/7
2008-07-18 12:31 am
Substitute a number for x and y and solve.
2008-07-18 12:29 am
1x=10/3
y=2/3
2.x=33/14
y=9/7
3.x=-9/7
y=73/7

hope it helps!
2008-07-18 12:26 am
Correctly.
Once you have the value of one variable, plug it back into one of the original equations to solve for y.

1) add the equations together and solve for x. Then solve for y as described above.

2) rewrite the first equation, replacing "4x" with "4(3-y/2)". Then solve for y as described above.
3) rewrite first equation, replacing the "-2y" with "-5x-4". Solve for x. Then solve for y as described above.
2008-07-18 12:45 am
1)
2x + y - 10 = 0 (solve by using substitution)
x - y - 4 = 0

2x + y - 10 = 0
y = 10 - 2x

x - y - 4 = 0
x - (10 - 2x) - 4 = 0
x - 10 + 2x - 4 = 0
x + 2x = 10 + 4
3x = 14
x = 14/3

2x + y - 10 = 0
2(14/3) + y - 10 = 0
28/3 + y - 10 = 0
y = 10 - 28/3
y = 30/3 - 28/3
y = 2/3

∴ x = 14/3 , y = 2/3

= = = = = = = =

2)
4x - 5y = 3 (solve by using substitution)
x = 2 - (1/2)y

4x - 5y = 3
4(2 - y/2) - 5y = 3
8 - 2y - 5y = 3
-2y - 5y = 3 - 8
-7y = -5
y = -5/-7
y = 5/7

x = 3 - (1/2)y
x = 3 - (1/2)(5/7)
x = 3 - 5/14
x = 42/14 - 5/14
x = 37/14

∴ x = 37/14 , y = 5/7

= = = = = = = =

3)
3x - 2y - 1 = 0 (solve by using addition)
y = 5x + 4

3x - 2y - 1 = 0
3x - 2y = 1

y = 5x + 4
-5x + y = 4
2(-5x + y) = 2(4)
-10x + 2y = 8

...3x - 2y = 1
+ -10x + 2y = 8 (addition)
--------------------------
-7x = 9

-7x = 9
x = 9/-7
x = -9/7

y = 5x + 4
y = 5(-9/7) + 4
y = -45/7 + 4
y = -45/7 + 28/7
y = -17/7

∴ x = -9/7 , y = -17/7


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