can someone solve this 10+3(2x-6)<=4(2x-7)?

10+3(2x-6)<=4(2x-7)
10 + 6x - 18 ≤ 8x - 28
6x - 8 ≤ 8x - 28
6x + 20 ≤ 8x
20 ≤ 2x
10 ≤ x

x ≥ 10

10 + 3(2x - 6)<=4(2x - 7) . . .first expand all terms:

10 + 6x -18 <= 8x - 28 . . .Combine like terms:

6x - 8 <= 8x - 28 . . .subtract 6x from and add 28 to both sides:

20 <= 2x . . .divide by 2

10 <= x

First step is to distribute and then simplify each side of the inequality.
10 + 3( 2x - 6 ) < = 4 ( 2x - 7 )
10 + 6x - 18 <= 8x - 28
6x - 8 <= 8x - 26
-6x +6x - 8 <= -6x + 8x - 28
-8 <= 2x - 28
28 - 8 <= 2x - 28 + 28
20 <= 2x
20/2 <= 2x ? 2
10 <= x or
x >= 10
[ 10, +∞)

develop bothside
10+6x-18<=8x-28
6x-8<=8x-28
-2x<=20
x>=10

10+ 6x-18<=8x-28
-8=<2x-28
2x=>20
x=>10

10+3(2x-6)=<4(2x-7)
10+6x-18=<8x-28
6x-8=<8x-28
-2x=<-20
-x=<-10
10=<x

10 + 3(2x - 6) ≦ 4(2x - 7)
10 + 3*2x - 3*6 ≦ 4*2x - 4*7
10 + 6x - 18 ≦ 8x - 28
6x - 8x ≦ -10 + 18 - 28
-2x ≦ -20
x ≧ -20/-2
x ≧ 10