can someone solve this 10+3(2x-6)<=4(2x-7)?

2008-07-16 4:24 pm

回答 (7)

2008-07-16 4:29 pm
✔ 最佳答案
10+3(2x-6)<=4(2x-7)
10 + 6x - 18 ≤ 8x - 28
6x - 8 ≤ 8x - 28
6x + 20 ≤ 8x
20 ≤ 2x
10 ≤ x

x ≥ 10
2008-07-16 11:34 pm
10 + 3(2x - 6)<=4(2x - 7) . . .first expand all terms:

10 + 6x -18 <= 8x - 28 . . .Combine like terms:

6x - 8 <= 8x - 28 . . .subtract 6x from and add 28 to both sides:

20 <= 2x . . .divide by 2

10 <= x
2008-07-16 11:41 pm
First step is to distribute and then simplify each side of the inequality.
10 + 3( 2x - 6 ) < = 4 ( 2x - 7 )
10 + 6x - 18 <= 8x - 28
6x - 8 <= 8x - 26
-6x +6x - 8 <= -6x + 8x - 28
-8 <= 2x - 28
28 - 8 <= 2x - 28 + 28
20 <= 2x
20/2 <= 2x ? 2
10 <= x or
x >= 10
[ 10, +∞)
2008-07-16 11:31 pm
develop bothside
10+6x-18<=8x-28
6x-8<=8x-28
-2x<=20
x>=10
2008-07-16 11:30 pm
10+ 6x-18<=8x-28
-8=<2x-28
2x=>20
x=>10
2008-07-16 11:30 pm
10+3(2x-6)=<4(2x-7)
10+6x-18=<8x-28
6x-8=<8x-28
-2x=<-20
-x=<-10
10=<x
2008-07-16 11:28 pm
10 + 3(2x - 6) ≦ 4(2x - 7)
10 + 3*2x - 3*6 ≦ 4*2x - 4*7
10 + 6x - 18 ≦ 8x - 28
6x - 8x ≦ -10 + 18 - 28
-2x ≦ -20
x ≧ -20/-2
x ≧ 10


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