1-3[2x-2(2x-4)] ???

1-3*[2x-2*(2x-4)] ???

-2*(2x-4) = -4X+8

so we get

1-3*[2x-2*(2x-4)]
= 1-3*(2x-4x+8)
= 1-3*(-2x+8)

-3*(-2x+8) = 6x-24

so we get

1-3*[2x-2*(2x-4)]
= 1+6x-24
= 6x-23

Order of Operations:
1 - Parentheses
2 - Exponents
3 - Multiplication and Division
4 - Addition and Subtraction

Start with the innermost parentheses and work out:
1-3[2x-2(2x-4)]
Now distribute the 2 to get rid of parentheses:
1-3[2x-4x+8)
Combine like terms:
1-3[-2x+8]
Distribute the 3:
1+6x-24
Combine like terms:
6x-23

***Always remember when distributing a negative number to reverse the signs when multiplying.

we are not solving we are simplifyying
1-3[2x-2(2x-4)]
1-3[2x-4x +8]

1-3 [ -2x+8]
1+6x +24
6x +25

1 - 3 [ 2x - 4x + 8 ]
1 - 3 [ 8 - 2x ]
1 - 24 + 6x
6x - 23

Unlike many,you produced a very clear question by using brackets ----well done !

1 - 3[2x - 2(2x - 4)]
= 1 - 3[2x - 2*2x + 2*4]
= 1 - 3[2x - 4x + 8]
= 1 - 3[-2x + 8]
= 1 + 3*2x - 3*8
= 1 + 6x - 24
= 6x + 1 - 24
= 6x - 23

multiply the ones in the brackets first (remember to use the FOIL-First Outside Inside Last)
then multiply the whole thing by -3 (pay attention to the sign before 3)
and then just add one or just combine like terms. here goes:

1-3[2x-2(2x-4)]
1-3[4x^2-6x-4x+8]
1-3[4x^2-10x+8]
1-12x^2+30x-24
-12x^2+30x-23

1-3[2x-4x+8]=1-3[8-2x]=1-24+6x=6x-23

1-3[2x-2(2x-4)]
1-3[2x-4x+8]
1-3[8-2x]
1-24+6x
6x-23

1 - 3[2x - 2(2x - 4)]
= 1 - 3(2x - 4x + 8)
= 1 - 3(-2x + 8)
= 1 + 6x - 24
= 6x - 23