pls solve the following eq?

yup. It's x=6, y=2. Times each term of the second equation by negative four and then add the two equations together. Solve for "y". Then plug that value of "y" back into one of the original equations to find "x".

there are 2, which one do you want me to solve (btw i do know that there is not just one solution to 1 equation in 2 unknowns)

multiply the 2nd equation by -4 to eliminate x
4x-5y=14
-4 (x+3y=12)


add the 2 equations
4x - 5y =14
-4x - 12y = -48
----------------------
-17y = -34

divide both sides by -17

y = 2
4x - 5(2)= 14
4x - 10 = 14
4x = 14+10
4x=24
x=6

x=6, y=2

x=12-3y
4(12-3y)-5y=14
48-12y-5y=14
-17y=14-48
17y=34
y=2
x=12-3*2
x=12-6
x=6

--Ana-Maria

12x - 15y = 42
5x + 15y = 60-----ADD

17x = 102
x = 6

6 + 3y = 12
3y = 6
y = 2

x = 6 , y = 2

4x - 5y = 14 (solve by using substitution)
x + 3y = 12

x + 3y = 12
x = 12 - 3y
4x = 4(12 - 3y)

4x - 5y = 14
4(12 - 3y) - 5y = 14
48 - 12y - 5y = 14
-12y - 5y = 14 - 48
-17y = -34
y = -34/-17
y = 2

4x - 5y = 14
4x - 5(2) = 14
4x - 10 = 14
4x = 14 + 10
4x = 24
x = 24/4
x = 6

∴ x = 6 , y = 2

is it linear eqs?
Here's the answer

4x-5y=14 ------1st eq.
x+3y=12 -------2nd eq.

From 2 eq.
x=12-3y--------3rd eq.

substituting in 1 eq.
4(12-3y)-5y=14
48-12y-5y=14
-12y-5y=14-48
-17y=-34
y=-34/-17
y=2

In 3 eq.
x=12-3y
x=12-(3*2)
x=12-6
x=6

so
x=6
y=2

4x-5y=14
x+3y=12 ---------x= -3y+12

then substitute:
4(-3y+12)-5y=14
-12y+48-5y=14

combine like terms:
-12y-5y= -48+14
-17y= -34 (divide bothe sides by -17)
y=34/17
y=2


afterwards substitute the value of y to any equationn to find the value of x

x+3y=12
x= -3(2)+12
x= -6+12
x=6


Answers:
x=6
y=2

y=2
x=6
if you want the calculations just ask...
heck ill giv em to ya!

4x - 5y = 14
(x + 3y = 12) x 4

4x - 5y = 14
4x +12y = 48

4x-4x= 0
-5y - 12y = -17y
14- 48 = -34

-17y = -34
-y = -34/-17
-y= -2
y=2

4x - 5y =14 5y= 5x2 = 10
4x - 10 = 14
4x = 14+10
4x=24
x= 24/4
x=6

Y = 2 and x= 6?? did i do some kinda Finney Math?