A water pipe of internal diameter 2.6cm delivers water at a rate of 0.8m/s.
How much water comes out per second?
Given two right cylindrical vessels A and B. The base diameters od vessels A
and B are 4 cm and 12cm reapectively. Initially, A contains water to a depth
of 18cm and B is empty. The water in A is then poured into B .Find (a) the
water level in B and (b) the wetted surface area of B.
Maths!
2008-07-16 11:30 pm
回答 (1)
2008-07-17 12:51 am
✔ 最佳答案
1. For each second, water pass through the water pipe = 0.8m = 0.008cm Base area of the water pipe = pi * r^2 = (1.3^2)* pi (cm2)
Vol of water come out from the pipe of each second
= (1.3^2)* pi *0.008 (cm3) = 0.4247 (cm3)
2.
a) vol of water in A = pi*4 * 18= 72pi
water level in B = 72pi /( pi*(6^2) = 2 cm
b) wet surface = circumfercence of B * water level
= pi*12 * 2 = 75.40 (cm2)
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