{30-[(6+1)*(4-1)]+12}/3=?
Thx...（^ ^)..............................
Mathematics Q.
2008-07-16 10:58 pm
回答 (3)
2008-07-16 11:20 pm
✔ 最佳答案
答案如下：答案如下：圖片參考：http://i320.photobucket.com/albums/nn347/old-master/2008-07-16A.jpg?t=1216192611
2008-07-16 11:53 pm
{30-[(6+1)*(4-1)]+12}/3
=[30-(7*3)+12]/3
=(30-21+12)/3
=(9+12)/3
=21/3
=7
**因為先乘除後加減
**仲有要先計括號
**由小括號開始計起
=[30-(7*3)+12]/3
=(30-21+12)/3
=(9+12)/3
=21/3
=7
**因為先乘除後加減
**仲有要先計括號
**由小括號開始計起
參考: 我
2008-07-16 11:01 pm
Mathematics Q.
{30-[(6+1)*(4-1)]+12}/3=?
Thx...（^ ^)..............................
ANSWER: 7
{30-[(6+1)*(4-1)]+12}/3=?
Thx...（^ ^)..............................
ANSWER: 7
參考: 我
收錄日期: 2021-04-14 20:42:29
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https://hk.answers.yahoo.com/question/index?qid=20080716000051KK01474