Solve using Completing the square method: x^2 + 5x - 35 =3x?

x² + 2x - 35 = 0
(x + 1)² - 1 - 35 = 0
(x + 1)² = 36
x + 1 = \pm 6
x = -1 \pm 6 = -7, 5

x^2 + 5x - 35 = 3x
x^2 + 5x - 3x - 35 = 0
x^2 + 2x - 35 = 0
(x + 1)^2 - 36 = 0
(x + 1)^2 = 36
x + 1 = ±√36
x + 1 = ±6

x + 1 = 6
x = 6 - 1
x = 5

x + 1 = -6
x = -6 - 1
x = -7

∴ x = -7 , 5

x2 +2x-35
so
x+7times x-5
so x=5 and x=-7

initially to the asker, what's x2? Is it (x*2) or (x²)? It looks like as though the asker needs incorrect inquiries to be responded. purely as quickly as I went by using a number of the subjects, i'd desire to be certain that it replaced into x² and not 2x. to no longer be rude, yet I purely basically reported. by technique of how, for the respond: x²-8x=24, So: x²-5x-24=0. made of two numbers is -24. Sum of two numbers is -5. So the numbers are -8, 3. x²-5x-24=0, subsequently may be written as: x²+3x-8x-24=0, which may be written as: x(x+3)-8(x+3)=0, which provides: (x-8)(x+3).

x^2 + 2x + ? = 35 + ?

find ? the value that completes the square

for ax^2 + bx + c

a has to be one , it is one so u are ok

divide b by 2, then square it (b/2)^2

(2/2)^2 = 1^2 = 1

x^2 + 2x + 1 = 35 + 1

factor

(x + 1)(x + 1) = 36

(x + 1)^2 = 36

x + 1 = 6 x + 1 = -6

x = 5 and x = -7

x² + 2x - 35 = 0
(x² + 2x + 1) - 1 - 35 = 0
(x + 1)² = 36
(x + 1) = ± 6
x = 5 , x = - 7