Solve using completing the square or Square Root Rule?

2008-07-15 7:53 pm
2x^2 + 10 =210

回答 (9)

2008-07-15 8:02 pm
✔ 最佳答案
Divide by two to simplify:

x^2 +5 -105 = 0
x^2 -100 = 0
x^2 = 100
x= +/-10

{-10,10}
2008-07-15 7:59 pm
2x^2 = 200
Divide both sides by 2:
x^2 = 100
Therefore, x=+/-10
2016-05-25 3:48 am
Complete the square to form a perfect square trinomial x² + 24x + __? 24 x 24 = 576 x² + 24x + 576 Add or subtract the monomials. 6 – 12p5 – 3p + 8 – 8p5 14-20p5-3p Simplify. -2-5 -7 Multiply. 3ab(5a^2 + b) 15ba^3+3ab^2 Solve using square roots. Check your answer. x^2 = 100 Take the square root from both sides. x=10 simplify 6^4 x 6^1 6^5 Simplify completely. Type your answer as an integer with no exponent. 6^7/6^5 6^2 Good luck.
2008-07-17 11:01 pm
2 x² = 200
x² = 100
x = ± 10
2008-07-15 8:05 pm
2x^2 + 10 = 210
2x^2 = 210 - 10
2x^2 = 200
x^2 = 200/2
x^2 = 100
x = ±√100
x = ±10
2008-07-15 8:04 pm
subtract 10 from both sides, your equation:

2x² = 200

divide 2 to both sides:

x² = 100

take the square root of 100

x = 10

or

x = -10 because it's squared

Hope this helped! :]
2008-07-15 7:59 pm
2x²+ 10 = 210
2x² = 210 -10 = 200
x² = 100
x = 10.
2008-07-15 7:58 pm
2x^2+10=210

2x^2+10-10=210-10

2x^2=200
x^2=100
x=10
2008-07-15 7:57 pm


收錄日期: 2021-05-01 10:50:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080715115358AADzgWg

檢視 Wayback Machine 備份