Simplify, 10x^2 - 30x + 20 over x^2 - 1?
回答 (5)
2008-07-15 6:04 pm
✔ 最佳答案
10(x²-3x+2)/(x-1)(x+1)10(x-2)(x-1)/(x-1)(x+1)
(10x-2)/(x+1)
2008-07-15 6:39 pm
10x^2-30x+20 / x^2-1
10(x^2-3x+2) / (x-1)(x+1)
10(x-1)(x-2)/x-1)(x+1)
10 (x-2)/x+1
10(x^2-3x+2) / (x-1)(x+1)
10(x-1)(x-2)/x-1)(x+1)
10 (x-2)/x+1
2008-07-15 6:08 pm
(10x^2 - 30x + 20)/(x^2 - 1)
= 10(x^2 - 3x + 2)/(x^2 - 1)
= 10(x - 1)(x - 2)/(x + 1)(x - 1) (cancel out x - 1)
= 10(x - 2)/(x + 1)
= 10(x^2 - 3x + 2)/(x^2 - 1)
= 10(x - 1)(x - 2)/(x + 1)(x - 1) (cancel out x - 1)
= 10(x - 2)/(x + 1)
2008-07-15 6:06 pm
10x^2-20x-10x+20
10x(x-2)-10(x-2)
(x-2)(10x-10)
=10(x-2)(x-1) / (x-1)(x+1)
=10(x-2) / (x+1)
10x(x-2)-10(x-2)
(x-2)(10x-10)
=10(x-2)(x-1) / (x-1)(x+1)
=10(x-2) / (x+1)
2008-07-15 6:04 pm
10x^2 - 30x + 20 over x^2 - 1
10x^2 - 30x + 20 ----> divide 10 into this equation
10(x^2 - 3x + 2) over x ^2 -1
x^2 - 1 = (x - 1)(x + 1)
10(x^2 - 3x + 2) = 10(x - 2)(x - 1)
10(x - 2)(x - 1) over (x - 1)(x + 1)
Therefore 10(x - 2) over (x + 1) becuase (x - 1) cancel each other out
10x^2 - 30x + 20 ----> divide 10 into this equation
10(x^2 - 3x + 2) over x ^2 -1
x^2 - 1 = (x - 1)(x + 1)
10(x^2 - 3x + 2) = 10(x - 2)(x - 1)
10(x - 2)(x - 1) over (x - 1)(x + 1)
Therefore 10(x - 2) over (x + 1) becuase (x - 1) cancel each other out
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