因式分解題目3(15分)
Please answer all the question:
1)Factorize the following polynomials.
A.)x²+6x+5
B.)a²-6a-16
C.)m²-9m+18
D.)c²+c-20
E.)2+3x+x²
F.)3y²-7y-6
G.)2u²-7u+3
H.)3p²+16+14p
I.)r+2r-15
J.)-10-29s+3s²
K.)41r+2r²+20
I.)14-29x²+2x^4
2)The polynomial 3r²-59r-20 can be factorize to a form of(ar+b)(cr-d),where a,b,c,and d are positive integers.Find the value of a,b,c and d.
3)
A.)Factorize 2x²-x-15 and x²-4x+3
B.)Using the result of part (a),factorize (2x²-x-15)(x²-4x+3)
回答 (2)
1)Factorize the following polynomials.
A.)x²+6x+5 = (x+5)(x+1)
B.)a²-6a-16 = (a-8)(a+2)
C.)m²-9m+18 = (m-3)(m-6)
D.)c²+c-20 = (c+5)(c-4)
E.)2+3x+x² = (x+1)(x+2)
F.)3y²-7y-6 = (3y+2)(y-3)
G.)2u²-7u+3 = (2u-1)(u-3)
H.)3p²+16+14p = (3p+8)(p+2)
I.)r²+2r-15 = -------
J.)-10-29s+3s² = (3s+1)(s-10)
K.)41r+2r²+20 = (2r+1)(r+20)
I.)14-29x²+2x^4 = (2x²-1)(x²-14)
2)The polynomial 3r²-59r-20 can be factorize to a form of(ar+b)(cr-d),where a,b,c,and d are positive integers.Find the value of a,b,c and d.
3r²-59r-20 = (3r+1)(r-20)
a=3
b=1
c=1
d=20
3)
A.)Factorize 2x²-x-15 and x²-4x+3
2x²-x-15 = (2x+5)(x-3)
x²-4x+3 = (x-3)(x-1)
B.)Using the result of part (a),factorize (2x²-x-15)(x²-4x+3)
(2x²-x-15)(x²-4x+3)
=(2x+5)(x-3)(x-3)(x-1)
=(x-3)²(x-1)(2x+5)
1 I)果度ge 2次方係邊個位到
因為r²+2r-15同r+2r²-15都做到因式分解
我唔知你要做邊隻
參考: Me
1)Factorize the following polynomials.
A.)x+6x+5=(x+5)(x+1)//
B.)a-6a-16=(a-8)(a+2)//
C.)m-9m+18=(m-6)(m-3)//
D.)c+c-20=(c+5)(c-4)//
2008-07-15 22:07:20 補充:
E.)2+3x+x²=(x+2)(x+1)//
F.)3y²-7y-6=(3y+2)(3y-3)
G.)2u²-7u+3=(2u-1)(u-3)//
H.)3p²+16+14p=(3p+8)(p+2)//
I.)r+2r-15=(r-5)(r+3)//
J.)-10-29s+3s²=(3s+1)(s-10)//
2008-07-15 22:08:36 補充:
41r+2r^2+20=(r+20)(2r+1)//
I.)14-29x²+2x^4=(2x^2-1)(x^2-14)//
2008-07-15 22:09:24 補充:
2)The polynomial 3r²-59r-20 can be factorize to a form of(ar+b)(cr-d),where a,b,c,and d are positive integers.Find the value of a,b,c and d.
3r²-59r-20=(3r-4)(r+20)
so,a=1,b=20,c=3,d=4//
2008-07-15 22:10:32 補充:
3)
A.)Factorize
2x²-x-15 =(2x+5)(x-3)//
and
x²-4x+3=(x-3)(x-1)//
B.)Using the result of part (a),factorize
(2x²-x-15)(x²-4x+3)
=(2x+5)(x-3)(x-3)(x-1)
=(2x+5)(x-1)(x-3)^2//
收錄日期: 2021-04-25 14:45:36
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